A blog where I post solutions to the mechanics and statics problems that I encounter. Also many mastering engineering problems will be seen, so users of that program may find this blog interesting. The course uses the Hibbeler Statics textbook and some of the subjects covered include: Cartesian vectors, force resultants, force equilibrium, particle equilibrium, Hooke's Law, vector decomposition, etc. More to be added as those problems and topics are encountered.
Showing posts with label Dot Product. Show all posts
Showing posts with label Dot Product. Show all posts
Tuesday, October 6, 2015
2_3_e
Determine the angle
between the edges of the sheet-metal bracket.
Labels:
2,
Cartesian Vector,
Components,
Dot Product,
Force,
Force Projection,
Force Vectors,
Particles,
Position Vector,
Statics,
Unit Vector,
Vector
2_3_d
A force of F = {-40k} lb acts at the end of the pipe. Determine the magnitudes of the components F1 and F2 which are directed along the pipe’s axis and perpendicular to it.
2_3_c
Determine the angle
between the two cords
Labels:
2,
Cartesian Vector,
Components,
Dot Product,
Force,
Force Projection,
Particles,
Position Vector,
Resultant,
Statics,
Unit Vector,
Vector
2_3_b
Determine the magnitude of the projected component of r1 along r2, and the projection of r2 along r1.
2_3_a
Cable BC exerts a force of F = 28 N on the top of the flagpole. Determine the projection of this force along the z-axis of the pole.
Wednesday, September 23, 2015
3_3_d
Determine the smallest force F that must be applied along the rope in order to cause the curved rod, which has a radius of 5 ft, to fail at the support of C. This requires a moment of M = 80 lb
ft to be developed at C.
Wednesday, February 18, 2015
2: Notes
Scalars & Vectors
Scalar - any positive or negative physical quantity that can be completely specified by its magnitude Vector - any physical quantity that requires both a magnitude and a direction for its complete description
The resultant of several coplanar forces can easily be determined if an x, y coordinate system is established and the forces are resolved along the axes
Multiplication or division of a vector by a scalar will change only the magnitude of the vector.
If vectors are collinear, the resultant is simply the algebraic or scalar addition
Parallelogram Law
Two forces add according to the parallelogram law. The components form the sides of the parallelogram and the resultant is the diagonal.
Cartesian Vectors
Representation
V=Vxi+Vyj+Vzk
Magnitude
Direction
cosα = Vx/V
cosβ = Vy/V
cosγ = Vz/V
an easy way of obtaining these direction cosines is to form a unit vector UV in the direction of Vcosβ = Vy/V
cosγ = Vz/V
UV = V/|V| = Vx/V i + Vy/V j + Vz/V k
an important relation among the direction cosines can be formulated as
cos2α + cos2β + cos2γ = 1
Addition
VR = ΣV = ΣVxi + ΣVyj + ΣVzk
Position Vectors
if r extends from the origin of coordinates, O, to point P(x,y,z)
r=xi+yj+zk
for two vectors rA and rB, the position vector represented by the two of them isr=(xB-xA)i+(yB-yA)j+(zB-zA)k
The easiest way to formulate the components of a position vector is to determine the distance and direction that must be traveled along the x,y,z directions - going from the tail to the head of the vector
A force F acting in the direction of a position vector r can be represented in Cartesian form if the unit vector U of the position vector is determined and it is multiplied by the magnitude of the force, i.e. F=|F|u=|F|(r/|r|)
Dot Product
A⋅B = ABcosθ = AxBx + AyBy + AzBz
The magnitude of the projection of vector A along a line a whose direction is specified by ua is determined from the dot product |Aa| = A⋅ua
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